JEE Main • Mathematics

Complex Numbers & Quadratic Equations

Complete Revision Notes | JEE Main 2025–26

High Weightage • 4–6 Questions Expected

Complex Numbers – Basics

A complex number z = a + ib (a, b real)
Re(z) = a, Im(z) = b
✓ If Re(z) = 0 → purely imaginary
✓ If Im(z) = 0 → real number

Polar (Trigonometric) Form

z = r (cos θ + i sin θ)
where r = |z| = √(a² + b²), θ = arg(z)

General form: z = r [cos(2nπ + θ) + i sin(2nπ + θ)], n ∈ Z

Properties of Conjugate (¯z)

Basic
  • z = ¯z ⇔ z is real
  • z = –¯z ⇔ z is purely imaginary
  • ¯¯z = z
Real & Imaginary Part
  • Re(z) = (z + ¯z)/2
  • Im(z) = (z – ¯z)/(2i)
Operations
  • ¯(z₁ + z₂) = ¯z₁ + ¯z₂
  • ¯(z₁ – z₂) = ¯z₁ – ¯z₂
  • ¯(z₁z₂) = ¯z₁ ¯z₂
  • ¯(z₁/z₂) = ¯z₁/¯z₂ (z₂ ≠ 0)

Properties of Modulus |z|

Key Properties

  • |z| ≥ 0 ⇒ |z| = 0 iff z = 0
  • –|z| ≤ Re(z) ≤ |z|, –|z| ≤ Im(z) ≤ |z|
  • |z| = |¯z| = |–z|
  • |z|² = z ¯z
  • |z₁z₂| = |z₁||z₂| → |z₁z₂…zn| = |z₁||z₂|…|zn|
  • |z₁/z₂| = |z₁|/|z₂| (z₂ ≠ 0)
  • |z₁ ± z₂| ≤ |z₁| + |z₂| (Triangle inequality)

Argument of Complex Number

Quadrant-wise arg(z)
zPointarg(z)
1 + i(1,1)π/4
1 – i(1,–1)–π/4
–1 + i(–1,1)3π/4
–1 – i(–1,–1)–3π/4
Properties of Argument
  • arg(z₁z₂) = arg(z₁) + arg(z₂) + 2kπ (k = 0, ±1)
  • arg(z₁/z₂) = arg(z₁) – arg(z₂) + 2kπ
  • arg(zⁿ) = n arg(z) + 2kπ
  • arg(¯z) = –arg(z)
  • arg(z) = 0 ⇒ z is positive real

De Moivre’s Theorem & Cube Roots of Unity

[cos θ + i sin θ]ⁿ = cos(nθ) + i sin(nθ) (for any rational n)

Also valid for negative exponents with conjugate forms.

Cube Roots of Unity (Roots of x³ = 1)

Roots

1, ω, ω² where ω = –½ + i√3/2
ω² = –½ – i√3/2
1 + ω + ω² = 0
ω³ = 1, (ω²)³ = 1

Properties
  • ω³ = 1, 1 + ω + ω² = 0
  • ω³ᵏ = 1, ω³ᵏ⁺¹ = ω, ω³ᵏ⁺² = ω²

Quadratic Equation ax² + bx + c = 0 (a ≠ 0)

Discriminant D = b² – 4ac

Roots: α, β = [–b ± √D] / (2a)

Nature of Roots (a, b, c real)

ConditionNature of Roots
D > 0Two distinct real roots
D = 0Two equal real roots
D < 0Complex conjugate roots

Sum & Product of Roots

α + β = –b/a
αβ = c/a

Both roots positive → sum > 0, product > 0
Both roots negative → sum < 0, product > 0

Graph & Inequations

y = ax² + bx + c = a(x + b/(2a))² + (D/(4a))
Vertex: (–b/(2a), –D/(4a))

a > 0 → opens upwards (concave up)
a < 0 → opens downwards (concave down)

Quadratic Inequations

ax² + bx + c ≥ 0 or ≤ 0 are solved using sign chart and nature of roots.

Important Theorems

  • Factor Theorem: α root ⇒ (x – α) divides f(x)
  • Every odd degree polynomial has at least one real root
  • Rolle’s Theorem: f(a) = f(b) ⇒ ∃ c ∈ (a,b) where f'(c) = 0

JEE Main Tips & Weightage

One of the highest weightage chapters (4–6 questions every year).

Must Remember

  • All properties of conjugate, modulus, argument
  • Triangle inequality |z₁ + z₂| ≤ |z₁| + |z₂|
  • Cube roots of unity: 1 + ω + ω² = 0, ω³ = 1
  • Nature of roots based on discriminant
  • Vertex form and condition for common roots
  • Argument addition/subtraction with 2kπ